Mathematica ALmost got it, mathematical induction, writing terms seperatley

AI Thread Summary
The discussion revolves around proving the equality of two equations using mathematical induction, specifically by separating the k-th term from the first k terms. The user is attempting to apply the inductive hypothesis and perform algebraic manipulations to demonstrate this equality. They express difficulty in transforming the left-hand side of the equation to match the right-hand side, which is expected to be in the form of (k+1)*2^(k+3) + 2. Additional insights and examples are provided to clarify the process, emphasizing the importance of correctly applying the function and summation properties. The user is seeking further guidance on their algebraic manipulation to complete the proof.
mr_coffee
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Hello everyone I'm having problems on this last part of mathematical induction. I have to show that the two equations are equal to each other. The book shows a few examples which i will show below. They are writing the kst term separately from the first k terms.

Heres my problem firstly:
Prove by mathematical induction:
http://img219.imageshack.us/img219/1613/lastscancw1.jpg

My Goal is to prove that those 2 equations do infact equal each other, the boxed equations. Once I write the k term separatley then I go on to substitute from the inductive hypotheiss, then do some algebra.Examples of writing the terms seperately:
http://img295.imageshack.us/img295/9369/lastscan3cn3.jpg

Under my problem i attempted to mimic what they are doing, is that it or no? Any help would be great on explaining what they are doing here!

:biggrin:
 
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it should be

\sum_{i = 1}^{k + 2} i2^i = \left(\sum_{i = 1}^{k+1} i2^i \right) + (k+2)2^{k+2}


As a simple example consider:

\sum_{i=1}^{4}i = 1 + 2 + 3 + 4 = (1 + 2 + 3) + 4 = \left(\sum_{i=1}^{3}i \right) + 4


more generally, if f is a function defined on the integers, and a, b, and c are integers with a \leq b \leq c then,

\begin{align*}<br /> \sum_{i = a}^{c} f(i) &amp;= f(a) + f(a+1) + \ldots + f(b-1) + f(b) + f(b+1) + \ldots + f(c-1) + f(c) \\ <br /> &amp;= \left( f(a) + f(a+1) + \ldots + f(b-1) \right) + \left( f(b) + f(b+1) + \ldots + f(c-1) + f(c) \right) \\<br /> &amp;= \left( \sum_{i = a}^{b-1} f(i) \right) + \left( \sum_{i = b}^{c} f(i) \right) <br /> \end{align*}


in regards to your problem, f is the function
f(k) = k2^k
and a = 1, b = c = k + 2

Your proof up to this point looks great by the way, very nicely written.
 
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Thanks nocturnal, that explanation was very helpful. Sorry about the delayed responce.

I'm now having the following troubles, i can't seem to manipulate the left hand side of the equation to look like the right hand side.

This is my work:

http://img187.imageshack.us/img187/1449/lastscanfj5.jpg I'm suppose to get that to look like right hand side of the equation, (k+1)*2^(k+3) + 2, any help or suggestions would be great! I tried to factor and expand, and they dont' seem to work or maybe i can't see somthing.

THanks!
:biggrin:
 
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