Alternate Representations of Lorentz Generators Mμν

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sshaep
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I know the representations of Lorentz generators M[tex]\mu\nu[/tex] as 4X4 matrices.

This matrices satisfy the commutation relation(Lie algebra of O(3,1))

However I think these 4X4 matrix representations are not unique.

Is there any other representations satisfying the commutation relation? 2X2 matrix or

another?
 
on Phys.org
Yes, there are infinitely many representations of the Lorentz algebra. One trivial example is to form a set of 8x8 matrices by taking the Kronecker product of M with the 2x2 identity.
 
sshaep said:
Is there any other representations satisfying the commutation relation? 2X2 matrix or another?

Because [itex]SL \left(2 , \mathbb{C} \right)[/itex] is the universal cover of the restricted Lorentz group, they have isomorphic Lie algebras.
 
George Jones said:
Because [itex]SL \left(2 , \mathbb{C} \right)[/itex] is the universal cover of the restricted Lorentz group, they have isomorphic Lie algebras.

This means can I get the 2x2 representation of M[tex]\mu\nu[/tex] from SL(2,C)?

But how? What I know is [tex]\sigma_{\mu}A^{\mu} _{\phantom{\mu}\nu}}[/tex]=[tex]L\sigma_{\nu}L^{\dagger}[/tex]
 
Take

[tex] M^{0i} = \frac{i}{2} \sigma^{i}, \ \ M^{ij} = \frac{1}{2} \epsilon^{ijk}\sigma^{k}[/tex]

Also, if you define

[tex]\omega_{i0} = 2 Re(\alpha_{i}), \ \ \omega_{ij} = 2 \epsilon^{ijk} Im(\alpha_{k})[/tex]

then

[tex] 1 + \frac{i}{2}\omega_{\mu\nu}M^{\mu\nu} = \left( \begin {array}{rr} (1 + \alpha_{3}) & (\alpha_{1} - i \alpha_{2}) \\ (\alpha_{1} + i \alpha_{2}) & (1 - \alpha_{3}) \end {array} \right)[/tex]

represents elements of SL(2,C) infinitesimally close to the identity element.

regards

sam
 

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