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Am I doing anything opposite to this problem related to verifying Stokes' theorem?

  1. Oct 4, 2009 #1
    https://nrich.maths.org/discus/messages/27/147417.jpg [Broken]

    For the above problem, I simply take the curl of F and then take the cross product of it with the normal to the plane and integrate the whole thing with respect to the surface bounded by the plane.

    Now, my solution is as followed with the help of computer program (save some manual calculation):

    https://nrich.maths.org/discus/messages/27/147418.jpg [Broken]

    Now, why is my value negative? am I doing something opposite? I thought I take the right normal vector. My n ds = dr/dx cross with dr/dy multiplied by dx and dy = <1, 1/2, 1> dxdy

    So, the whole (double) integration is just
    curl of F dotted with <1,1/2,1> dydx where y goes from 0 to 8-2x and then x from 0 to 4.

    please help

    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Oct 4, 2009 #2
    Re: am I doing anything opposite to this problem related to verifying Stokes' theorem

    never mind...

    just figure out the -1/2 x of -1/2 x - yx should be +1/2 x.

    ignore this thread then...
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