Am i right? solving log functions

[A_Munk3y]

Am i right? :) solving log functions!

Homework Statement

solve the following equations

1. e^4x=25
2. ln(x²-8x+13)=0

The Attempt at a Solution

1.
lne^4x=ln25
=> 4x=ln25
=> x=(1/4)ln25
x=0.8047

2.
ln(x²-8x+13)=0
=> e⁰=x²-8x+13
=> 1= x²-8x+13
=> x²-8x+12=0
(x-6)(x-2) = 0

So x=2 or 6.

 

[micromass]

Seems fine

 

[Mentallic]

All good, but being a little picky, if you were asked to leave the first one in exact form you might lose half a mark for not converting log(25) into 2log(5)

 

[A_Munk3y]

Thanks :)
Yea, the teach said that we don't have to worry about conversions and simplifying much. But thanks for pointing that out