AM radio signal superimpostion/modulation

  • Thread starter sillyquark
  • Start date
  • #1
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Homework Statement



Describe how the concept of wave superimposition is used to create AM radio waves.

Homework Equations





The Attempt at a Solution



O.K, I am not sure that I understand how this works. In the picture attached it shows the carrier frequency inside of the audio signal. The amplitude changes over time, so is the amplitude not proportional to the wavelength or frequency? If that is the case then would I be correct in saying that constructive/destructive wave interference is used to superimpose the amplitude of the carrier frequency to be similar with the audio signal's wavelength. Wave demodulation for AM signals measures the amplitude over time so that the wavelength can be known. With the wavelength and speed of light one can calculate the frequency of the audio signal, which is then amplified and converted into sound through the speakers.

Is this more or less correct?
 

Attachments

  • AM superimposition.png
    AM superimposition.png
    34.9 KB · Views: 493

Answers and Replies

  • #2
Delphi51
Homework Helper
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superimpose the amplitude of the carrier frequency to be similar with the audio signal's wavelength
Change the last word to "amplitude". AM is amplitude modulation, not frequency modulation. There is, of course a broadening of the frequency range from virtually a single carrier frequency to the range carrier - audioFreq to carrier + audioFreq, but you have not been asked about that.
 
  • #3
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So, superimposing the amplitude of the carrier frequency to be similar with the audio signal's amplitude/time gives us wavelength or frequency?
 
  • #4
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Dear sillyquark, AM wave is generated by modulating the carrier wave's amplitude proportional to the signal wave's instantaneous y offset from the x axis (Suppose that you draw a standard Y-X coordinate to plot the signal wave), your attachment plot is an AM wave, with Both Side-Band
 
  • #5
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You didn't really answer my question, you just stated what the attachment displays.
 
  • #6
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You didn't really answer my question, you just stated what the attachment displays.

Sorry about that, I didn't get your idea just now.

I guess you're asking about this [tex]Y_{am}(t)=(A_c+A_s \cdot cos(2 \pi f_s t)) \cdot cos(2 \pi f_c t)[/tex] ?

I'm not familiar with Latex in this forum, it took me so much time to adapt to it....
 
  • #7
Delphi51
Homework Helper
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So, superimposing the amplitude of the carrier frequency to be similar with the audio signal's amplitude/time gives us wavelength or frequency?
It doesn't "give us wavelength or frequency". It gives the complex waveform at the bottom of your attachment picture. It has the carrier frequency waveform modulated in amplitude according to the audio signal.
 
  • #8
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O.K, I understand the concept but not thoroughly. Thanks for the help, this is all I should need for the answer. Genxium, what are the variables in the equation you posted?
 
  • #9
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O.K, I understand the concept but not thoroughly. Thanks for the help, this is all I should need for the answer. Genxium, what are the variables in the equation you posted?

A : Amplitude , f: frequency , c: carrier , s: signal.

and this is the simpliest example while the signal wave is a sinusoid wave, but according to Fourier's Theorem, any real wave could be regarded as a superposition of many sinusoid waves, this basic form is still useful in analysis
 
  • #10
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Great, thanks, you've helped a lot.
 
  • #11
George Jones
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A : Amplitude , f: frequency , c: carrier , s: signal.

and this is the simpliest example while the signal wave is a sinusoid wave, but according to Fourier's Theorem, any real wave could be regarded as a superposition of many sinusoid waves, this basic form is still useful in analysis

And, in this case, a standard simple identity involving [itex]\cos A \cos B[/itex] gives the superposition.
 

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