Ampere's Law for current carrying wire

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SUMMARY

The discussion focuses on applying Ampere's Law to derive the magnetic field inside a current-carrying wire, specifically showing that the magnetic field B is equal to (1/2)μJr, where J represents the constant current density. Participants clarify that in the context of the problem, r refers to the radius of the wire, not its length. The equation ∫B*ds=μI is established as the starting point, with the need to integrate over the circular path around the wire. The conversation highlights the importance of understanding the relationship between current (I) and current density (J) in cylindrical coordinates.

PREREQUISITES
  • Ampere's Law
  • Understanding of magnetic fields
  • Concept of current density (J)
  • Basic calculus for integration
NEXT STEPS
  • Study the derivation of Ampere's Law in cylindrical coordinates
  • Learn about the relationship between current (I) and current density (J) in conductive materials
  • Explore the implications of magnetic fields in current-carrying conductors
  • Review integration techniques for circular paths in physics
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the principles of magnetic fields in conductive materials.

btpolk
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Homework Statement



Use Ampere's Law to show that the equation for the magnetic field inside a current carrying wire is (1/2)μJr where J is the current density (assumed constant).


Homework Equations



∫B*ds=μI

The Attempt at a Solution



∫B*ds=μI

B*ds=B(ds)cosθ I think θ is 0 in this situation?

∫Bds=μI I believe r is length. If so would I=Jr?

∫Bds=μJr

From here I don't know what to do. What would my limits of integration be?
 
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hi btpolk! :smile:
btpolk said:
I believe r is length. If so would I=Jr?

no, r is radius

and J is the current per cross-section area
 
That said, I'm guessing I would treat the wire as a cylinder and the limits of integration would be 0 to 2pi? Also where does the J come in? Would it be some kind of substitution for I?
 

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