Ampere's Law in Classical Electrodynamics

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Ampere's Law is valid in classical electrodynamics but requires strong symmetries, making it challenging to apply to short conductors passing through a loop due to edge effects. The integral of the magnetic field along the loop is equal to the enclosed current times the permeability constant, but this relationship holds more clearly for long conductors. Modifications, such as including the displacement current, are necessary for accurate applications, especially in varying geometries. For short conductors, a complete current loop is essential to maintain the validity of the law, as neglecting parts of the circuit can lead to inaccuracies. Understanding these nuances is crucial for correctly applying Ampere's Law in different scenarios.
CHUKKY
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I do not know but I do not know if Ampers law is valid for short conductors passing through a loop. I did integrate and my integral was different from the expected I*U. The law seems to be valid only when long conductors pass through a loop but not short ones. Can anyone explain what am missing?
 
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Ampere's law requires very strong symmetries to use properly. It's always valid, but the integral is very hard if edge effects are present.
 
but is their a way to show that no matter the dimension of the conductor passing through the loop the integral of the magnetic field along the loop is the enclosed current times the permeability constant.or was this law arrived by empirical and not theoretical means.
 
Well, you need to modify Ampere's law a little bit to include the so-called "displacement current". It is "verified" theoretically because it is one of Maxwell's equations. But of course, all physical laws must be verified experimentally.
 
but wld displacement current avail for short conductor?nd it was a steady current.
 
You need a current loop. The only reason you can neglect the "loop" part for the long wire is that you can say the other parts of the wire are far away. If you have a short conductor, you need to close the circuit to have current.
 
Awesome i just taught about that. kk And so what you saying is that due to the fact that electrons need to drift along the curved path, electric field intensity changes and Maxwell's law then avail right?if I am right reply me. And thank you very much for resolving this issue if my post is right. If my post aint right please correct.
 
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