Amplifier efficiency calculations?

  • Thread starter MehhShell
  • Start date
  • #1
4
0
Would the efficiency calculated using the P output/P input x 100 get the same answer as calculating the efficiency using the RMS input and output values? If so why?
 

Answers and Replies

  • #2
vk6kro
Science Advisor
4,081
40
No, it isn't the same.

Efficiency is the power out into a resistive load divided by the DC power into the amplifier, multiplied by 100 to get percentage.

The power into the resistive load is usually caused by an AC voltage across the load.

The power into the amplifier is the (DC supply voltage) times the (DC current) supplied to the transistors in the amplifier.
 
Last edited:

Related Threads on Amplifier efficiency calculations?

Replies
11
Views
30K
Replies
3
Views
4K
  • Last Post
Replies
5
Views
91K
  • Last Post
Replies
1
Views
8K
Replies
1
Views
3K
  • Last Post
Replies
5
Views
2K
Replies
5
Views
2K
Replies
9
Views
103
  • Last Post
Replies
1
Views
723
  • Last Post
Replies
2
Views
2K
Top