An electron shot from the back of a T.V. help?

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Homework Help Overview

The problem involves calculating the magnetic field required for an electron traveling at a significant fraction of the speed of light to maintain a circular path with a specified radius in a cathode ray tube setup.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the formula for the radius of circular motion in a magnetic field, questioning the accuracy of calculations and the values used for mass, charge, and speed of the electron.

Discussion Status

There is ongoing verification of calculations among participants, with some expressing uncertainty about their results and others confirming the correctness of certain values. Multiple interpretations of the calculations are being explored.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. The discussion reflects attempts to clarify assumptions and definitions related to the problem.

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Homework Statement



If I shoot an electron from the back of a TV at a screen towards the front at .5c (e= speed of light) What magnetic field must be in the coils around the cathode ray tube (picture tube) if the electron would have made a circle radius 30m if it hadn't hit the screen and made it glow. (your TV show)

Homework Equations



r= (mv)/qB

The Attempt at a Solution



Using the equation rearranged to solve for B:

B=mv/qr

mass of an electron = 9.1 x 10^-31
charge of an electron = 1.602 x 10^-19
.5c=...well it's half of the spd of light so I assume : 1.5 x 10^8 since the spd of light is 3x10^8 if I remember correctly.
and radius = 30m

so:

B= (9.1x10^-31)(1.5x10^8)/(1.602x10^-19)(30)
B= .026?

Could someone check if I did this correctly, did I forget something?
 
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Your calculation is wrong. Check it.
 
Hm.

Now I'm getting

B = 3.06x10^-5

Is that correct?

I tried taking baby steps to see what I did incorrectly but I'm not sure if it's helping.
 
Yes. It is correct.
 
Thanks, now I know those baby steps helped.
 
acsis said:
Hm.

Now I'm getting

B = 3.06x10^-5

Is that correct?

I tried taking baby steps to see what I did incorrectly but I'm not sure if it's helping.

Have checked those calculations and got 2.8402x10^-5... :rolleyes:
 

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