MTd2 said:
Sorry... But I don't get where you are trying to go.
I have this idea cooking in my head, so I am bouncing it off here. It concerns a general approach to framing fields. This is just the preliminary parts here, and I am slamming out some of the notation --- I hope I get the indices etc more or less right.
A differential form and its dual vector [itex]\vec v[/itex], [itex]\underline f[/itex] is seen in the product
[tex]
\vec{v} \underline{f}~=~v^i\vec{\partial_i}\underline{dx}^j f_j~=~v^if_i[/tex]
What I did was to assume that the differential form had the form [itex]{\underline f}~=~e^{V}{\underline dx}[/itex]. The contraction is then
[tex]
v^i\vec{\partial_i}\underline{dx}^je^{V_j}~=~v^ie^{2V_j}{\partial_i}\underline{dx}^j~+~v_i(\partial_iV_j){\underline dx}^j.[/tex]
Then consider a transformation [itex]e^{V}~\rightarrow~e^{-i\chi^\dagger}e^{V}e^{i\chi}[/itex] which gives a variation in V as
[tex]
\delta V~=~i(\chi~-~\chi^\dagger)~-~{i\over 4}[(\chi~+~\chi^\dagger),~V][/tex]
and the deviation in the contraction is
[tex]
\langle v,~F\rangle~\rightarrow~v_ie^{V_i}~+~e^{-i\chi^\dagger}\big(\partial_iV~+~i\partial_i(\chi~-~\chi^\dagger)\big)e^{i\chi}[/tex]
We might now want a form of this contraction which is gauge covariant. So to do this we back track and consider [itex]y^i~=~x^i~+~\lambda^\alpha\sigma^i_{\alpha{\dot\beta}}\lambda^{\dot\beta}[/itex]. We then have that
[tex]
dy^i~=~dx^i~+~ d\lambda^\alpha\sigma^i_{\alpha{\dot\beta}}\lambda^{\dot\beta}~+~\lambda^\alpha\sigma^i_{\alpha{\dot\beta}}d\lambda^{\dot\beta}[/tex]
The differential operators dual to this system are
[tex]
\partial_i,~D_\alpha~=~\partial_\alpha~+~i\sigma^i_{\alpha{\dot\beta}}{\bar\lambda}^{\dot\beta}\partial_i[/tex]
Then for the vector [itex]{\underline f}~=~e^{V}{\underline dy}[/itex] there exists a differential form contraction will result in
[tex]
\omega_A~=~\sigma^i_{\alpha{\dot\beta}}\partial_i V d\lambda^{\dot\beta}~+~d\lambda^\alpha\sigma^i_{\alpha{\dot\beta}}\lambda^{\dot\beta}~+~\lambda^\alpha\sigma^i_{\alpha{\dot\beta}}d\lambda^{\dot\beta},[/tex]
where the left index A runs over i and [itex]\alpha[/itex]. This is analogous to the differential forms [itex]\omega^0~=~\gamma(dx^0~-~u^0 dx)[/itex] and [itex]\omega^i~=~\gamma(dx^i~-~u^idt)[/itex] corresponding to special relativity. This is a Finsler bundle, and from this a generalized lifting condition (an Euler-Lagrange equation constraint) will be derived for the framing of fields.
An invariant vector for the contraction [itex]v^\alpha (D_\alpha\Phi) {\underline d\lambda})[/itex] for [itex]\Phi~=~(1/4) {\bar D}{\bar D}V[/itex] will define under the contraction
[tex]
\Phi_\alpha~=~D_\alpha\Phi~=~\frac{1}{4}{\bar D}{\bar D}D_\alpha V[/tex]
which if we impose the holomorphic condition [itex]D_\alpha\chi^\dagger~=~0[/itex] then this is gauge invariant for [itex]V~\rightarrow~V~+~\chi~+~\chi^\dagger[/itex]. In general
[tex]
\Phi_\alpha~=~\frac{1}{4}{\bar D}{\bar D}e^{-V}D_\alpha e^V[/tex]
which is also gauge covariant as [itex]\Phi_\alpha~\rightarrow~e^{-i\chi}\Phi_\alpha e^{i\chi}[/itex]