An object falls a distance s given as s=16t^2. find instanteneous rat

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SUMMARY

The discussion centers on calculating the average speed and average rate of change of distance for an object falling under the equation s=16t² between the time intervals t=3 and t=5. The average rate of change is defined as the total distance traveled divided by the total time, contrasting with instantaneous speed calculations. The user initially misinterprets the problem by focusing on instantaneous speed rather than the average speed over the specified interval. Correct calculations reveal that the average speed between t=3 and t=5 must be derived from the total distance fallen during that period.

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An object falls a distance s given as s=16t^2.

WHAT is the change of in distance, pr distance travelled, from t=3 and t=5?
What is the average rate of change of distance compared to time inthat time interval?
What is the average speed in that time interval?

Please help. I did values between t=4 and t=4.1 and instantaneous speed was approaching 128.
That was the example in the book.

Yet when i tried to do values between 3 and 3.1. my answer is way off. WHat is the problem asking me for?


ie when t=3; s=16x9=144
when t=3.1; s=16x9.61=153.76 then, 153.76-144=9.76/.1= 97.6

what am I doing wrong?
 
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Hi TitoSmooth! :smile:
TitoSmooth said:
… Yet when i tried to do values between 3 and 3.1. my answer is way off. WHat is the problem asking me for?

You're only doing the speed at 3.

The question doesn't ask for that, it asks for the average for the whole time between 3 and 5. :wink:
 
TitoSmooth said:
An object falls a distance s given as s=16t^2.
WHAT is the change of in distance, pr distance travelled, from t=3 and t=5?
How far had it fallen between t=0 and t= 3? How far had it fallen between t= 0 and t= 5?
So how far did it fall between t= 3 and

What is the average rate of change of distance compared to time inthat time interval?
Average rate of change is distance traveled divided by time

What is the average speed in that time interval?
"Speed" is "rate of change of distance"!

Please help. I did values between t=4 and t=4.1 and instantaneous speed was approaching 128.
That was the example in the book.
This problem does not ask for instantaneous speed. It asks for average speed.

Yet when i tried to do values between 3 and 3.1. my answer is way off. WHat is the problem asking me for?


ie when t=3; s=16x9=144
when t=3.1; s=16x9.61=153.76 then, 153.76-144=9.76/.1= 97.6

what am I doing wrong?
 

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