An obtuse triangle and its circumcenter

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I'm having a bit of difficulty proving this, but this is what I have so far:

Let a circle with a center O and a diameter AD. Let triangle ABC be a triangle with all points on the circle and angle A be greater than 90. Because of III. 20, and BOC is 2 times the size of angle A.

This is all I can reason through. I can see that it works on GSP, but I haven't been able to create a synthetic proof.
 
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Could be my English fails me, but I have no idea what you are trying to prove.
 
I'm trying to prove that the circumcenter of an obtuse triangle lies outside of the triangle.
 
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