Analog of Gauss' law in gravity

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Gauss's law for gravitation states that the integral of the gravitational field over a closed surface is equal to -4πGm, where G is the gravitational constant and m is the enclosed mass. This law parallels Gauss's law for electrostatics but includes a negative sign due to the attractive nature of gravity. The gravitational field, denoted as g, is defined similarly to the electric field, with the force on a mass μ being Fg = μg. Despite its significance, Gauss's law for gravity is less commonly known among physicists. A brief explanation can help clarify its principles effectively.
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Gauss law in case of sphere which has charge ##q## is ##\oint \vec{E}\cdot d\vec{S}=\frac{q}{\epsilon_0}##

Is there some anologone for case of sphere with mass ##m## such that
##\oint \vec{G}\cdot d\vec{S}=4\pi \gamma m ## and what is ##\vec{G}## in that case?
 
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Yes - it is Gauss' law for gravitation. Note that it differs from Gauss' law in electrostatics by the presence of a minus sign on the right:
\oint_{\partial V} \vec{g} \cdot d\vec{S} = -4\pi Gm
This is because gravitation is strictly attractive, while the electrostatic force can be either attractive or repulsive. The field ## \vec{g} ## is the gravitational field, defined completely analogously to the electric field whereby the force experienced by a particle of mass ## \mu ## in the field is ## \vec{F}_{g} = \mu \vec{g} ##.
 
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Likes Dr. Courtney
https://en.wikipedia.org/wiki/Gauss's_law_for_gravity

Gauss's law for gravity is not nearly as well known. I recall some years ago my wife gave a talk in a physics department and referred to it.

There were plenty of physicists in the room who were not familiar with the idea, but everyone quickly grasped it with a 30 second explanation.
 
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