Graduate Analytical Integration of a Difficult Function

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The discussion revolves around the analytical integration of a complex function involving exponential terms and a square root in the denominator. Participants are exploring whether the integral converges and under what conditions, particularly focusing on its behavior near zero and at infinity. Concerns are raised about the integrability of poles and the boundedness of the integral, with suggestions to simplify the integrand for better analysis. One contributor notes that while the integral appears manageable between zero and beta, the tail from beta to infinity presents challenges, being purely imaginary and infinite. The conversation highlights the integral's relevance in chemical reaction rate studies and the complexities involved in its evaluation.
junt
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Is it possible to integrate the following function analytically?

##\int_{0}^{\infty} \frac{\exp{-(\frac{A}{\tau}+B\tau+\frac{A}{\beta-\tau})}}{\sqrt{\tau(\beta-\tau)}}d\tau,##

where ##A##, ##B## and ##\beta## are real numbers. What sort of coordinate transformation makes the integral bounded? Is it even bounded? Are these poles integrable?

Any help is much appreciated!
 
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Can you provide a context of where you got this problem?
 
jedishrfu said:
Can you provide a context of where you got this problem?
Integrals like this appear when one is looking at chemical reaction rates. The exponent is basically the classical action. A and B contains space coordinates, which will be integrated after integral over ##\tau## has been performed.
 
Hi junt:

I think I understand that you are asking about whether the integral is finite. I think it is easy to see that the integrand behaves OK at infinity. It is a bit trickier to consider behavior at zero. Can you simplify the integrand behavior near zero and see if the integral of the simplification is OK? That is , consider the integral from zero to ε<<1 of a simplified integrand between zero and ε.

Regards,
Buzz
 
I've played a bit with WolframAlpha and it suggests that between 0 and ##\beta## it should be fine but the tail from ##\beta## to ##\infty## is purely imaginary and also infinite.
 
SlowThinker said:
is purely imaginary
Sure, since the expression under the root becomes negative
 

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