Angular Acc. Homework: Calculate Centripetal & Angular Acc.

AI Thread Summary
The discussion centers on calculating angular and centripetal acceleration for an airplane making a circular turn. The angular velocity was determined to be 0.02 rad/s, and the centripetal acceleration calculated as 3.62 m/s². It is clarified that with constant speed, both angular acceleration and tangential acceleration are zero. The relationship between angular acceleration and constant angular velocity is confirmed, reinforcing the understanding of the concepts involved. The conversation concludes with a positive acknowledgment of the learning process.
Jam51
Messages
32
Reaction score
0

Homework Statement


An airplane makes a circular turn of radius 9 km at a constant speed of 650 km/h. Calculate the magnitude of the plane's a. angular velocity, b. centripetal acceleration, c. angular acceleration, d. tangential acceleration

Homework Equations


w = v/r
aR = w^2r

The Attempt at a Solution



I found angular velocity to be 0.02rad/s and centripetal acceleration to be 3.62m/s^2

If the speed is constant would the angular and tangential acceleration be zero? I'm not sure that I am understanding the theory behind this.
 
Physics news on Phys.org
Definitely :smile:. Angular acceleration ## \alpha = {\Delta \omega\over \Delta t} = 0 ## for constant angular velocity ##\omega##.
And tangetial acceleration is ##\alpha r##; both are constant in your exercise. On to the next one !
 
  • Like
Likes Jam51
Thanks
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top