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Xlorep

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Note: This is similar to 2 previous questions I've seen here (https://www.physicsforums.com/showthread.php?t=261193"), and while this is my first post, I've lurked/found this site to really be helpful in getting me to be able to figure out how to solve problems I have with my physics homework.

Two pulley wheels, one of radius 0.3 m and the other of radius 0.82 m, are mounted rigidly on a common axle. The rotational intertia of the two pulleys, which are clamped together, is 3.3 kg·m². A mass of 44 kg mass is attached on the left and a mass of 37 kg mass on the right, as shown.

Find the angular acceleration of the system. Take the clockwise direction to be positive. The acceleration of gravity is 9.8 m/s². Answer in units of rad/s².

ΣΤ = Iα

ΣΤ = Τ1 + Τ2

So, the process I followed was this:

I found the torques for each mass & radius:

Τ1 = -(m1)g(R1)sin(90) --> (negative because going CCW)

Τ2 = (m2)g(R2)sin(90) --> (positive because going CW)

Therefore: ΣΤ = (m2)g(R2) - (m1)g(R1) = g(m2R2 - m1R1)

Which means: g(m2R2 - m1R1) = Iα

α = g(m2R2 - m1R1)/I

Checking the units, I should get rad/s²:

m/s²·(kg·m)/kg·m²

Which is: (m²·kg)/(s²·kg·m²)

Results in: rad/s²

So my units check out.

So, with the following variables (I'm hoping I got the left/right values correct):

Plugging these in, I get:

α = [9.8]([37][0.82] - [44][0.3])/[3.3]

α = (9.8)(30.34 - 13.2)/3.3

α = (9.8)(17.14)/3.3

α = (167.972)/3.3

α = (167.972)/3.3

α = 50.90060606 rad/s²

Which, apparently, is wrong. So I'm at a loss. What did I do wrong? Or rather, what would be a good hint for me to figure out where I went wrong?

(and yes, I know it seems strange for an α > g... that doesn't seem to logically follow for me)

## Homework Statement

Two pulley wheels, one of radius 0.3 m and the other of radius 0.82 m, are mounted rigidly on a common axle. The rotational intertia of the two pulleys, which are clamped together, is 3.3 kg·m². A mass of 44 kg mass is attached on the left and a mass of 37 kg mass on the right, as shown.

Find the angular acceleration of the system. Take the clockwise direction to be positive. The acceleration of gravity is 9.8 m/s². Answer in units of rad/s².

## Homework Equations

ΣΤ = Iα

ΣΤ = Τ1 + Τ2

## The Attempt at a Solution

So, the process I followed was this:

I found the torques for each mass & radius:

Τ1 = -(m1)g(R1)sin(90) --> (negative because going CCW)

Τ2 = (m2)g(R2)sin(90) --> (positive because going CW)

Therefore: ΣΤ = (m2)g(R2) - (m1)g(R1) = g(m2R2 - m1R1)

Which means: g(m2R2 - m1R1) = Iα

α = g(m2R2 - m1R1)/I

Checking the units, I should get rad/s²:

m/s²·(kg·m)/kg·m²

Which is: (m²·kg)/(s²·kg·m²)

Results in: rad/s²

So my units check out.

So, with the following variables (I'm hoping I got the left/right values correct):

- g = 9.8 m/s²
- m1 = 44 kg
- R1 = 0.3 m
- m2 = 37 kg
- R2 = 0.82 m
- I = 3.3 kg·m²

Plugging these in, I get:

α = [9.8]([37][0.82] - [44][0.3])/[3.3]

α = (9.8)(30.34 - 13.2)/3.3

α = (9.8)(17.14)/3.3

α = (167.972)/3.3

α = (167.972)/3.3

α = 50.90060606 rad/s²

Which, apparently, is wrong. So I'm at a loss. What did I do wrong? Or rather, what would be a good hint for me to figure out where I went wrong?

(and yes, I know it seems strange for an α > g... that doesn't seem to logically follow for me)

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