Angular Acceleration (Grindstone Problem)

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SUMMARY

The discussion revolves around calculating the angular acceleration of a grindstone that completes 20.0 revolutions in 8.00 seconds. The correct approach involves using the rotational kinematic equation θ = ω_initial * t + 0.5 * α * t², where θ is the angular displacement in radians. The participants clarify that the initial angular velocity is zero, and they derive the final angular velocity as 125.6 rad/s. The calculated angular acceleration is 15.7 rad/s², which is not one of the provided options, indicating a potential error in the problem setup or interpretation.

PREREQUISITES
  • Understanding of rotational kinematic equations
  • Knowledge of angular displacement and angular velocity
  • Familiarity with the relationship between revolutions and radians
  • Basic principles of uniform angular acceleration
NEXT STEPS
  • Review the derivation of the rotational kinematic equation θ = ω_initial * t + 0.5 * α * t²
  • Learn how to convert between revolutions and radians for angular motion
  • Explore examples of angular acceleration calculations in physics
  • Study the SUVAT equations for linear motion and their analogs in rotational motion
USEFUL FOR

Students studying physics, particularly those focusing on rotational dynamics, and educators seeking to clarify concepts of angular motion and acceleration.

gcombina
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Homework Statement


A grindstone, initially at rest, is given a constant angular acceleration so that it makes 20.0 rev in the first 8.00 s. What is its angular acceleration?

(a) 0.313 rad/s2 (c) 2.50 rad/s2 (e) 3.93 rad/s2

(b) 0.625 rad/s2 (d) 1.97 rad/s2

Homework Equations


Rotational Kinematic equations

The Attempt at a Solution



Ok so I am using the equation ω = ω (initial) + ∝ T
BUT my answer is the wrong one. It seems that I have to use this equation ω^2 = ω (initial) ^2 + 2∝Θ
but what do I put in liew of "Θ"?

I just don't understand why is that I have to use that equation?
 
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gcombina said:
Ok so I am using the equation ω = ω (initial) + ∝ T
BUT my answer is the wrong one. It seems that I have to use this equation ω^2 = ω (initial) ^2 + 2∝Θ
but what do I put in liew of "Θ"?
I don't see how you can use that equation directly since you don't know the final angular speed.
These equations for uniform angular acceleration are completely analogous to the SUVAT equations for uniform linear acceleration.
linear...angular
distance...angle
speed...angular speed
acceleration..angular acceleration
Given a distance, an initial speed and a time, what equation would you use to find the acceleration?
 
haruspex said:
I don't see how you can use that equation directly since you don't know the final angular speed.
These equations for uniform angular acceleration are completely analogous to the SUVAT equations for uniform linear acceleration.
linear...angular
distance...angle
speed...angular speed
acceleration..angular acceleration
Given a distance, an initial speed and a time, what equation would you use to find the acceleration?
angular acceleration = change in angular velocity/time

=(final ang vel-initial ang vel)/time

here, initial ang vel =0
final ang vel = 20 rev/s = 125.6 rad/s (there are 2 pi radians/rev)

so, ang accel = (125.6rad/s)/8s=15.7rad/s/s or

I still don't have the answer!
 
gcombina said:
angular acceleration = change in angular velocity/time
Yes, but that's not what I asked. Forget this question and angular motion for the moment. In linear uniform acceleration,
haruspex said:
Given a distance, an initial speed and a time, what equation would you use to find the acceleration?
I.e., what SUVAT equation relates distance, time, initial velocity, and acceleration?
 
haruspex said:
Yes, but that's not what I asked. Forget this question and angular motion for the moment. In linear uniform acceleration,

I.e., what SUVAT equation relates distance, time, initial velocity, and acceleration?

θ = ω t + 1/2 t^2

that one
 
gcombina said:
θ = ω t + 1/2 t^2

that one
Yes (except that you missed out one symbol).
 

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