Angular Acceleration of a Rigid Bar

AI Thread Summary
To determine the angular acceleration of the rigid bar system with two identical masses, first calculate the moment of inertia using the formula I=Ʃ(r^2)(m), which results in I=md^2 - 2adm + 2ma^2. After finding the moment of inertia, the next step involves applying the rotational analog of Newton's second law, τ = Iα, where τ is the net torque acting on the system and α is the angular acceleration. Consider the forces acting on the masses when the system is released from the horizontal position, as they will influence the torque and thus the angular acceleration. Understanding the direction of rotation and the forces involved will guide the calculation of the angular acceleration.
reuben19
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Homework Statement



Two identical masses with a mass of m each are connected by a rigid bar of negligible mass and rotate in a vertical plane in an anti-clockwise direction.

Homework Equations



If the system is released from rest when it is in a horizontal position, determine the angular acceleration of motion.

The Attempt at a Solution



So far, this is my progression towards a final solution. Firstly, find the moment of inertia of the system:

I=Ʃ(r^2)(m)
= (d-a)^2(m) + (a)^2(m)
= (d-a)(d-a)(m) + (a)^2(m)
= md^2 - 2adm + 2ma^2

I'm getting stuck after I do this, because I have no idea what to do after I find the moment of inertia in order to find the angular acceleration. I have attached an image to help the visualisation of the situation. Your help would be greatly appreciated! :)







 

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Think about what causes the system to have an angular acceleration. Which way will it tend to rotate when you let it go? Why? What is the rotational analog of Newton's second law of motion?
 
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