Angular acceleration of off balance wheel starting from rest

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To find the angular acceleration of a 30 kg wheel with a center of mass offset and a radius of gyration of 0.15 m, the moment of inertia is calculated as I = mk^2, resulting in 0.675 kg*m². The normal force is determined to be 294.3 N, equating the forces in the vertical direction. The equation relating the moment about the center to angular acceleration is set up but the user struggles to complete the calculations. The expected answer for angular acceleration is 10.3 rad/s², indicating a need for clarification on the problem setup and calculations.
Arin
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Homework Statement


A 30 kg wheel has a center of mass 0.1 m left from the center of the wheel and radius of gyration KG = 0.15 m. Find the angular acceleration if the wheel is originally at rest. The radius of the wheel is 0.25m.

Homework Equations


I=mk^2
T=f*d
M=I*a
Fn acting bottom in Y direction = m*g

The Attempt at a Solution


I=mk^2=(30)*(15^2)=0.675kg*m^2
Fx=0

Fn=(30*9.81)=294.3N
Sum of force in Y: Fn-mg=mass*angular acceleration*radius to center
294.3-294.3=30*a*0.1

Moment about center =ig*a*radius to center of mass
(294.3*.1)=(.675)*a*.1

... lost from here?

Apparently answer is 10.3 rad/s^2

Help please! Been working on this for hours
 
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I think we need the complete problem statement as it was provided to you, including the illustration. [emoji998]
 

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