Angular and Linear Motion problem

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Homework Help Overview

The problem involves calculating the angular velocity of a nail lodged in a car tire, given the car's speed and the distance of the nail from the center of the wheel. The subject area includes concepts of angular and linear motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between linear speed and angular velocity, questioning how to incorporate the car's speed into the calculation. There is also a focus on determining the circumference of the circle traced by the nail.

Discussion Status

The discussion is active, with participants exploring different aspects of the problem, including unit conversions and the implications of the car's speed on the nail's motion. Some guidance has been offered regarding the relationship between distance traveled and revolutions made.

Contextual Notes

Participants express frustration with unit conversions in the imperial system, which may affect their calculations. There is an acknowledgment of the complexity involved in converting between units of distance.

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Homework Statement



Automobile Tire: If a car runs over a nail at 55 mi/hr and the nail is lodged in the tire tread 13 in. from the center of the wheel, then what is the angular velocity of the nail in radians per hour?


Homework Equations



w = alpha/time

a = s / r


The Attempt at a Solution



I am not really sure where to start on this, obviously 13 in. is the radius, but I am unsure of how to get the angle alpha without a sector length. I assume it has something to do with the given 55 mph but don't see where it goes in.
 
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If it is lodged 13 inches from the centre of the tyre, then what is the circumference of the circle it makes around it?


p.s. there's no way I'm going to help with the units of that flawed imperial system.
x inches = 1 mile, where x is some crazy and unnecessarily complicated number.
 
yeah, it is 63360 into 1 mile. quite absurd but what can I do :(

The circumference I get is .001289163652 mi.
 
Move out of the US haha :-p

Ok so if the car is moving at 55mi/h and the circumference of the nail is ... that many miles, then how many revolutions will be made in an hour?
 
If only it were that simple!

Thanks for your help, I have it understood now! :)
 
It IS that simple :wink: No problem, have a nice day.
 

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