Angular Frequency for Small Oscillations

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SUMMARY

The discussion centers on calculating the angular frequency (ω) for small oscillations of a physical pendulum, specifically a uniform disk with a radius of 4.4 m and mass of 9 kg. The formula used to determine angular frequency is ω = √(mgd/I), where 'm' is mass, 'g' is the acceleration due to gravity (9.8 m/s²), 'd' is the distance from the pivot to the center of mass (1.364 m), and 'I' is the moment of inertia. The user successfully solved the problem after researching the concept independently.

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  • Understanding of physical pendulums
  • Familiarity with the moment of inertia
  • Basic knowledge of angular frequency
  • Concept of small oscillations in physics
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  • Study the derivation of the moment of inertia for various shapes
  • Learn about the dynamics of physical pendulums
  • Explore the effects of damping on oscillatory motion
  • Investigate the relationship between angular frequency and oscillation amplitude
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[SOLVED] help with homework problem

Homework Statement


A uniform disk of radius 4.4 m and mass 9 kg is suspended from a pivot 1.364 m above its center of mass. The acceleration of gravity is 9.8 m/s^2. Find the angular frequency w for small oscillations.

The Attempt at a Solution


I'm just wondering what does this question mean by finding the angular frequency for "small oscillations." Any help will be appreciated. Thanks!
 
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physical pendulum

If pushed slightly to one side, the disk would oscillate like a pendulum.
 
never mind. i figured it out. my professor didn't cover it yet but I looked it up. w=square root of mgd/I
 

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