Angular frequency of a mass between two springs.

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A mass M suspended between two springs with different spring constants (k and 3k) oscillates with an angular frequency derived from the net force equation. The net force is expressed as F(net) = Mg - 2kx, leading to the angular frequency ω = (2k/M)^(1/2) after a variable switch to z. The discussion emphasizes that the frequency remains the same whether calculated using the variable z or directly from x, as both represent simple harmonic motion. The equilibrium position is where the forces from the springs balance the gravitational force. The conversation also touches on the challenges of switching variables and the impact of fatigue on problem-solving.
Aesteus
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Homework Statement



A mass M is suspended from the ceiling by a spring with spring constant k, and from the floor by a spring with spring constant 3k. Find the frequency of the mass' oscillation.

Homework Equations



F=ma

The Attempt at a Solution



F(net) = Mg + kx - 3kx = Mg - 2kx

performing a variable switch z= x - Mg/2k, I simplified the equation and set it equal to F(net) = Ma.

Ma = -2kz ... so therefore ω = (2k/M)^1/2

As you see, I performed a variable switch and solved the angular frequency for z. Now, how do I go about switching back to x?
 
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Aesteus said:

F=ma

The Attempt at a Solution



F(net) = Mg + kx - 3kx = Mg - 2kx

performing a variable switch z= x - Mg/2k, I simplified the equation and set it equal to F(net) = Ma.

Ma = -2kz ... so therefore ω = (2k/M)^1/2

As you see, I performed a variable switch and solved the angular frequency for z. Now, how do I go about switching back to x?


z= x - Mg/2k. Is not x=z+Mg/2k? :biggrin:

ehild
 
:) very good

The problem is that I'm trying to switch back to x from my z-based frequency equation ω=(k/M)^1/2. And how do I do that? .... Or is there another way?
 
The frequency is the same either you solve for x or z. z is a simple harmonic motion: z=Asin(ωt), with ω=sqrt(2k/M). x is an SHM + constant, but ω does not change.

If you do not like to use the new variable, try to find the solution directly for x of form x(t)=Asin(ωt)+B, (B is a undefined constant, you get if you substitute x into the original equation).

Physically, the springs change length with respect to their unstretched length when the mass is placed between them, and the mass will vibrate around that equilibrium point where the forces from the spring cancel with gravity. What is the change of length of both springs?

ehild
 
Ah I see now. And I think part of the problem is that it's 5 a.m. here. :)
Also, do you think you can help me out with my other frequency problem? It's about finding angular frequency from potential energy. I've hit a mental wall.

https://www.physicsforums.com/showthread.php?t=593279
 
Aesteus said:
Ah I see now. And I think part of the problem is that it's 5 a.m. here. :)

Go to sleep. You will figure out the solution in your dreams:biggrin:

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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