Angular frequency of a mass between two springs.

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Homework Help Overview

The problem involves a mass suspended between two springs with different spring constants, seeking to determine the angular frequency of its oscillation. The context is rooted in mechanics and harmonic motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the net force acting on the mass and the variable switch used to simplify the equation. Questions arise about transitioning back to the original variable and the implications of using different variables for the oscillation frequency.

Discussion Status

Some participants have provided insights into the relationship between the variables and the nature of the oscillation. There is an acknowledgment that the frequency remains unchanged regardless of the variable used, and further exploration of the physical implications of the setup is suggested.

Contextual Notes

Participants note the time of day affecting their clarity, indicating potential cognitive fatigue. There is also mention of another related problem regarding angular frequency from potential energy, suggesting ongoing engagement with the topic.

Aesteus
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Homework Statement



A mass M is suspended from the ceiling by a spring with spring constant k, and from the floor by a spring with spring constant 3k. Find the frequency of the mass' oscillation.

Homework Equations



F=ma

The Attempt at a Solution



F(net) = Mg + kx - 3kx = Mg - 2kx

performing a variable switch z= x - Mg/2k, I simplified the equation and set it equal to F(net) = Ma.

Ma = -2kz ... so therefore ω = (2k/M)^1/2

As you see, I performed a variable switch and solved the angular frequency for z. Now, how do I go about switching back to x?
 
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Aesteus said:

F=ma

The Attempt at a Solution



F(net) = Mg + kx - 3kx = Mg - 2kx

performing a variable switch z= x - Mg/2k, I simplified the equation and set it equal to F(net) = Ma.

Ma = -2kz ... so therefore ω = (2k/M)^1/2

As you see, I performed a variable switch and solved the angular frequency for z. Now, how do I go about switching back to x?


z= x - Mg/2k. Is not x=z+Mg/2k? :biggrin:

ehild
 
:) very good

The problem is that I'm trying to switch back to x from my z-based frequency equation ω=(k/M)^1/2. And how do I do that? .... Or is there another way?
 
The frequency is the same either you solve for x or z. z is a simple harmonic motion: z=Asin(ωt), with ω=sqrt(2k/M). x is an SHM + constant, but ω does not change.

If you do not like to use the new variable, try to find the solution directly for x of form x(t)=Asin(ωt)+B, (B is a undefined constant, you get if you substitute x into the original equation).

Physically, the springs change length with respect to their unstretched length when the mass is placed between them, and the mass will vibrate around that equilibrium point where the forces from the spring cancel with gravity. What is the change of length of both springs?

ehild
 
Ah I see now. And I think part of the problem is that it's 5 a.m. here. :)
Also, do you think you can help me out with my other frequency problem? It's about finding angular frequency from potential energy. I've hit a mental wall.

https://www.physicsforums.com/showthread.php?t=593279
 
Aesteus said:
Ah I see now. And I think part of the problem is that it's 5 a.m. here. :)

Go to sleep. You will figure out the solution in your dreams:biggrin:

ehild
 

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