Angular Momentum Conservation -- Rope Problem

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SUMMARY

The discussion centers on the conservation of angular momentum in a scenario where a man swings on a rope and climbs upward. As he climbs at a constant speed v, his angular speed increases due to the change in the direction of his velocity vector, which is no longer perpendicular to the rope. This results in the tension force doing work on him, allowing for an increase in speed without generating net torque, thus conserving angular momentum.

PREREQUISITES
  • Understanding of angular momentum and its conservation principles
  • Familiarity with basic mechanics, particularly forces and torque
  • Knowledge of vector components and their implications in motion
  • Concept of tension force in rotational systems
NEXT STEPS
  • Study the principles of angular momentum conservation in rotating systems
  • Explore the relationship between tension forces and work done in mechanics
  • Learn about the effects of changing velocity components on angular motion
  • Investigate torque and its role in rotational dynamics
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Physics students, educators, and anyone interested in understanding the dynamics of rotational motion and the conservation laws in mechanics.

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Say there is a man swinging in space on a rope attached to a pivot. The man is rotating at some constant angular speed w.

Now he climbs up the rope at some constant speed v. Apparently the angular momentum is conserved. As a result his speed increases. However, how does his speed increase if there is no force in the tangential direction, because angular momentum is conserved and there can't be a force here as it would cause torque.I solved it
 
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Do you wish to share your solution?
 
pixel said:
Do you wish to share your solution?

Basically as soon as the man starts climbing there is a component of velocity that is no longer perpendicular to the rope since he is climbing upward. As a result the tension force can do work and increase speed, however though the speed increases the force still points toward the origin and there is therefore no net torque.
 

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