Angular momentum for third electron of Lithium

Click For Summary
The discussion focuses on calculating the angular momentum and energy of the third electron in a Lithium atom, specifically in its second orbit. The energy formula provided is E = -2π²e⁴mZ²/n²h², leading to a proposed energy value of -9π²e⁴m/2h². The angular momentum is calculated using the formula L = nh/2π, resulting in a value of h/π. However, it is noted that these equations are primarily applicable to the Li²⁺ ion, as the Bohr Model is designed for single-electron systems. The conversation emphasizes the need for careful consideration when applying these equations to the Lithium atom versus its ion.
xiphoid
Messages
57
Reaction score
0

Homework Statement


For the third electron of Lithium atom moving in its permissible orbit, the values of angular momentum and the energy are?


Homework Equations


E= -2π2e4mZ2/n2h2
Third electron is in the second orbit


The Attempt at a Solution


The value for energy should be -9∏2e4m/2h2
Correct me if i am wrong for the above answer,
Angular momentum= nh/2∏
So its value should h/∏

Am i right?
 
Physics news on Phys.org
These equations are only applicable for Li2+ ion, as Bohr Model are only applicable for Single electron species.
 
So, what do you think, my answer is right?
AGNuke said:
These equations are only applicable for Li2+ ion, as Bohr Model are only applicable for Single electron species.
 
Can't say about Li "atom". Talk about Li "ion". Then your answer may be right, simple substitution.

Well, owing to the fact you asked multiple questions, I guess you are studying Bohr Model.
 

Similar threads

Replies
6
Views
4K
Replies
1
Views
2K
Replies
17
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
10K
Replies
5
Views
3K