dextercioby said:
Since the 'ladder operators' are not (essentially) self-adjoint, there's no significance of their eigenvalues whatsoever.
Thanks dextercioby. Being very new to the concepts of Hermitian operators, I am obviously having a hard time grasping this explanation but I will continue to research the subject.
My question stems from something I read on OEIS related to NMR spectroscopy. Stanislav Sykora, among other things, maintains a dll for Mnova software. It is used for NMR functionality. On
http://oeis.org/A003991, he comments on the intensity of the transition between the states of spin being related to these ladder operators. Is his statement incorrect? If correct, doesn't this give significance to their eigenvalues?
"Consider a particle with spin S (a half-integer) and 2S+1 quantum states |m>, m = -S,-S+1,...,S-1,S.
Then the matrix element <m+1|S_+|m> = sqrt((S+m+1)(S-m)) of the spin-raising operator is the
square-root of the triangular (tabl) element T(r,o) of this sequence in row r = 2S, and at offset o=2(S+m).
T(r,o) is also the intensity |<m+1|S_+|m><m|S_-|m+1>| of the transition between the states |m> and |m+1>.
For example, the five transitions between the 6 states of a spin S=5/2 particle have relative intensities 5,8,9,8,5.
The total intensity of all spin 5/2 transitions (relative to spin 1/2) is 35, which is the tetrahedral number A000292(5).
[Stanislav Sykora, May 26 2012]"