Angular momentum ladder operators and state transitions

JeremyEbert
Messages
204
Reaction score
0
What is the significance of the ladder operators eigenvalues as they act on the different magnetic quantum numbers, ml and ms to raise or lower their values?
How do their eigenvalues relate to the actual magnetic transitions from one state to the next?
 
Last edited:
Physics news on Phys.org
Since the 'ladder operators' are not (essentially) self-adjoint, there's no significance of their eigenvalues whatsoever.
 
dextercioby said:
Since the 'ladder operators' are not (essentially) self-adjoint, there's no significance of their eigenvalues whatsoever.

Thanks dextercioby. Being very new to the concepts of Hermitian operators, I am obviously having a hard time grasping this explanation but I will continue to research the subject.

My question stems from something I read on OEIS related to NMR spectroscopy. Stanislav Sykora, among other things, maintains a dll for Mnova software. It is used for NMR functionality. On http://oeis.org/A003991, he comments on the intensity of the transition between the states of spin being related to these ladder operators. Is his statement incorrect? If correct, doesn't this give significance to their eigenvalues?

"Consider a particle with spin S (a half-integer) and 2S+1 quantum states |m>, m = -S,-S+1,...,S-1,S.
Then the matrix element <m+1|S_+|m> = sqrt((S+m+1)(S-m)) of the spin-raising operator is the
square-root of the triangular (tabl) element T(r,o) of this sequence in row r = 2S, and at offset o=2(S+m).
T(r,o) is also the intensity |<m+1|S_+|m><m|S_-|m+1>| of the transition between the states |m> and |m+1>.
For example, the five transitions between the 6 states of a spin S=5/2 particle have relative intensities 5,8,9,8,5.
The total intensity of all spin 5/2 transitions (relative to spin 1/2) is 35, which is the tetrahedral number A000292(5).
[Stanislav Sykora, May 26 2012]"
 
That is correct, but the eigenvalues still mean nothing. The state vectors (kets) are not theirs, but pertain to the spin components (S_z most common).
 
dextercioby said:
That is correct, but the eigenvalues still mean nothing. The state vectors (kets) are not theirs, but pertain to the spin components (S_z most common).

Ah, I've heard them described as "in between the state vectors", this makes sense. Is the intensity of the transition between the states referring to the intensity of the magnetic moment? Does this have something to do with the Larmor frequency?

Thanks again for your responses.
 
JeremyEbert said:
Ah, I've heard them described as "in between the state vectors", this makes sense. Is the intensity of the transition between the states referring to the intensity of the magnetic moment? Does this have something to do with the Larmor frequency?

Thanks again for your responses.

I guess my question comes down to;
Can I visualize the ladder operator values as vector rejection values?

http://en.wikipedia.org/wiki/Vector_projection#Vector_rejection_3
 
Last edited:
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

Similar threads

Back
Top