A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end. The rod is initially at rest. A bullet traveling parallel to the horizontal surface and perpendicular to the rod with speed v strikes the rod at its center and becomes embedded in it. The mass of the bullet is one-fourth the mass of the rod.(adsbygoogle = window.adsbygoogle || []).push({});

What is the final angular speed of the rod?

Ok, so the answer is 6v/19L, but I don't know how to get there. I have been using angular momentum concepts, but I don't get that answer it wants.

Been on this question for many hours, thanks in advance

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# Homework Help: Angular Momentum of a uniform rod

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