1. The problem statement, all variables and given/known data a 1.5 kg pendulum bob swings in a vertical circle at the end of a 2m long string with negligible weight. If the bob is dropped from a height in which the string is horizontal and taut, what is the angular momentum at the bob's lowest point (in kgm/s^2)? a 40 b 10 c 30 d 20 e 50 2. Relevant equations L=Iw L=mrv L(initial)=L(final) 3. The attempt at a solution I tried using the formula v2=vo2+2aΔy to solve for linear velocity first. It would be v= sqrt(2*9.8m/s/s*2m) because it falls the length of the string to reach the horizontal correct? From there, I calculated v to be 6.26m/s, and then subbed that into L=mrv for a final answer of 18.78kgm2/s, but its a bit off the possible choices and I'm skeptical of my work. Any help would be greatly appreciated!