Angular Momentum (train on a track)

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The discussion focuses on calculating the angular speed of a wheel-mounted toy train track system. The total mass of the wheel and track is 3.59 kg, with a radius of 1.79 m. The toy train, weighing 0.203 kg, achieves a steady speed of 0.551 m/s. The relationship between linear and angular momentum is established by equating the linear momentum of the train (mv) to the angular momentum of the wheel (MV), leading to the conclusion that the angular speed of the wheel can be derived from these parameters.

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Can someone help with this? Thnx

A toy train track is mounted on a large wheel that is free to turn with negligible friction about a vertical axis as shown in the figure above. The mass of the wheel plus track is 3.59 kg and the radius is 1.79 m. Ignore the mass of the spokes and hub. A toy train of mass 0.203 kg is placed on the track and, with the system initially at rest, the electric power is turned on. The train reaches a steady speed of 0.551 m/s with respect to the track. What is the angular speed of the wheel?
 
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Equate mvr of the train to mvr of the track. Since r is the same for each, just set mv=MV.
 
Thanks much
 

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