Angular velocity find angular displacement

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The discussion revolves around calculating angular displacement and torque for a rotating body with a moment of inertia of 20 kgm² and an angular velocity defined by w(t) = 3t² - 4. The angular displacement over the first 3 seconds was found by integrating the angular velocity, resulting in a value of 15, which represents an angle without specific units. For torque at t=2, the angular acceleration was derived from the derivative of w(t), yielding 12, which when multiplied by the moment of inertia gives a torque of 240. Participants confirmed the calculations and clarified that the angular displacement is dimensionless, simply representing an angle. Overall, the calculations for both angular displacement and torque were validated as correct.
tachu101
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Homework Statement


A body with moment of inertia 20kgm^2 is rotating about a fixed axis with an angular velocity of w(t)= 3t^2-4

a. Through what angular displacement will the body move in the first 3 seconds
b. What is the new torque exerted on the object at t=2

Homework Equations


Angular Kinematics equations

The Attempt at a Solution



I integrated the angular velocity to get the displacement to be Theta(t)=t^3-4t ... then I evaluated the definite integral from 0 to 3 to get 15. But 15 What? Am I doing this right?

I don't know what to do for the second part. Does anyone know?
 
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b) What's angular acceleration and torque formula?
 
torque = Ia so it would then be derivative of w(t)= 3t^2-4 to get 6t evaluated at 2 gets 12. Then you do 12 times 20 to get 240?
 
Does any of this look good?
 
Anyone?
 
Looks good to me.
 
tachu101 said:
A body with moment of inertia 20kgm^2 is rotating about a fixed axis with an angular velocity of w(t)= 3t^2-4

a. Through what angular displacement will the body move in the first 3 seconds
b. What is the new torque exerted on the object at t=2

I integrated the angular velocity to get the displacement to be Theta(t)=t^3-4t ... then I evaluated the definite integral from 0 to 3 to get 15. But 15 What? Am I doing this right?

Hi tachu101! :smile:

(have an omega: ω and a theta: θ :wink:)

Yes, that's fine … and the 15 has no dimensions … it's just an angle (in degrees or radians, depending on what w is, so you needn't say).
tachu101 said:
torque = Ia so it would then be derivative of w(t)= 3t^2-4 to get 6t evaluated at 2 gets 12. Then you do 12 times 20 to get 240?

Also fine (though you could have stated it a little more logically :wink:)
 

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