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## Homework Statement

I am asked to find the angular velocity of a falling rod in the instant that the rod meets the horizontal. The system is set up in this image:

The only force acting on the rod is gravity

## Homework Equations

U = (1/2)MgL

K = (1/2)Iw

^{2}

K

_{f}+ U

_{f}= K

_{i}+ U

_{i}

## The Attempt at a Solution

Can I solve this by using the potential energy of the rod with this equation:

U = (1/2)MgL

and then equating that to the Mechanical Energy at the point that it meets the horizontal?

I know the moment of inertia of the rod so if I do (1/2)MgL = (1/2)Iw

^{2}and solve for omega, is that correct?

Also, when finding the initial potential energy, should i use the full length of the rod or only the length to the center of mass?

Thank you!