Angular velocity when mass is added at center of rotation

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When a mass is added to a spinning system, the conservation of angular momentum dictates that the spin rate will change depending on the mass's moment of inertia. If the mass is not already spinning, it will require angular inertia to match the spin rate, which results in a decrease in the spinner's angular velocity. The discussion highlights that if the mass drops tangentially, it retains angular momentum, and the spinner's rate may not change significantly. However, if the mass is dropped directly into the lap and is not spinning, it will slow down the spinner as it "steals" angular speed to gain its own. Understanding these principles clarifies the relationship between mass, angular momentum, and rotational speed.
wootman23
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Homework Statement


A guy is spinning on a chair with his hands at rest on his lap. As he is spinning, a large mass drops into his hands/lap. Does the guy continue spinning at the same rate, a slower rate, or a faster rate?
This video demonstrates what happens when the guy drops mass:
http://media.pearsoncmg.com/aw/aw_0media_physics/vtd/video20.html

Please do not answer the question for me, but help me understand the problem and relevant equations.

Homework Equations


L = Iω = m(r^2)ω -----I think this this is the equation I need...

The Attempt at a Solution


If mass is added, shouldn't ω decrease due to the conservation of angular momentum?
But I did a quick experiment with my brother and I didn't seem to slow down...
 
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Angular momentum is not just a question of moving mass - the mass has to have some angular inertia (moment of inertia) to be interesting. Yes, if the mass is not already spinning, when dropped into your lap it will slow your spin, but it might not be that obvious. If the mass is narrow (a small heavy lump, or a tall pole) and drops into your lap at your axis of spin then it will have very little moment of inertia about that axis, so won't require much angular momentum to bring it up to your spin rate.
Dropping mass, as in the video, is rather different. The bags did not drop straight down; each flew off tangentially. This means they still had angular momentum about his axis. So in this case it does not matter how much moment the bags had about the axis, his spin rate will not change.
 
Ohhh so since the long, heavy bean bag isn't spinning as its dropped onto the guy's lap, it will will require some angular inertia to get it to spin...and to do this, it "steals" some angular speed from the guy which causes him to slow down? Do I have that right?
 
haruspex said:
Angular momentum is not just a question of moving mass - the mass has to have some angular inertia (moment of inertia) to be interesting. Yes, if the mass is not already spinning, when dropped into your lap it will slow your spin, but it might not be that obvious. If the mass is narrow (a small heavy lump, or a tall pole) and drops into your lap at your axis of spin then it will have very little moment of inertia about that axis, so won't require much angular momentum to bring it up to your spin rate.
Dropping mass, as in the video, is rather different. The bags did not drop straight down; each flew off tangentially. This means they still had angular momentum about his axis. So in this case it does not matter how much moment the bags had about the axis, his spin rate will not change.


Ohhh so since the long, heavy bean bag isn't spinning as its dropped onto the guy's lap, it will will require some angular inertia to get it to spin...and to do this, it "steals" some angular speed from the guy which causes him to slow down? Do I have that right?
 
wootman23 said:
Ohhh so since the long, heavy bean bag isn't spinning as its dropped onto the guy's lap, it will will require some angular inertia to get it to spin...and to do this, it "steals" some angular speed from the guy which causes him to slow down? Do I have that right?

Yes.
 
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haruspex said:
Yes.

Yup, you were right! Thank you for the explanation and confirmation!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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