Another leverage problem

  • Thread starter Ted Farkas
  • Start date
  • #1
19
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breakout leg.JPG
Hi,

This is another machine we have, with all the info I have recieved thus far regarding leverage.

Would I be correct in saying the output force is 177/574 x 5.1 ton giving aprrox 1.5 ton (F2).

The red rotates anti clockwise at the pivoit - this I would assume becomes harder because the pnuematic ram described as force F! compresses and rotates increasing the leverage slightly as R177 gets slighly bigger & cylinder volume compresses further.

thanks
Ted
 

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  • #2
Merlin3189
Homework Helper
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looks ok to me. I'd prefer brackets to show whether you meant 177/(574 x 5.1 ) or (177/574) x 5.1, but I get the same answer as you, so you must have done the latter.

You are also right to think about the changes as the lever rotates, moving the point of application and direction of the forces. The mechanical advantage could well vary as a result.
 
  • #3
JBA
Science Advisor
Gold Member
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You are making progress in your analyses; now that you are using a rudimentary schematic rather than a full assembly for your analyses. It also makes it much easier for forum members to evaluate your result. All of the above appears correct to me.
 
  • #4
19
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Hi

Thanks guys for your responses. It's giving everything a lot more clarity. Yep I probably need to put my equations in excepted format as well to tidy things up.

Thanks
Brett
The circle method has really been a great help (cad makes if super easy)
 

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