Another Really Easy Group Calculations which i cant do

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SUMMARY

The discussion focuses on proving the equation a3ba-3 = b8 given the condition aba-1 = b2. The user attempted various multiplication strategies, including left and right multiplying by a2 and a-2, but was unable to derive the proof. Key insights include recognizing that ba-1 = a-1b2 and ab = b2a, which are crucial for manipulating the expressions.

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Homework Statement


prove that if aba-1=b2

then a3ba-3=b8

The Attempt at a Solution



Ive tried lots of different things, none of which have worked.

i trield left and right multiplying by a^2 and a^-2 but couldn't figure it out.

I know there is some magical trick but i cannot for the life of me figure it out.
 
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There's no real way to give you a hint so I'll just do the first step:

Note that [tex]ba^{-1}=a^{-1}b^2[/tex] and [tex]ab=b^2a[/tex]

[tex]a^3ba^{-3}=a^2b^2a^{-2}=aabba^{-1}a^{-1}[/tex]
 

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