Answer: Expand (z+1)^5: 5z^4 + 10z^3 + 10z^2 + 5z^1 + 1

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SUMMARY

The expansion of the expression (z+1)^5 results in the polynomial 1 + 5z + 10z^2 + 10z^3 + 5z^4 + z^5. The discussion clarified that if the expression were (z-1)^5, the signs of the coefficients would alternate due to the negative base. Specifically, the terms would be 1 - 5z + 10z^2 - 10z^3 + 5z^4 - z^5. Understanding the impact of the binomial theorem on sign changes is crucial for accurate polynomial expansion.

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andrey21
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I simply have to expand (z+1)^5

I think I have the solution I am just unsure about the signs:z^5 5z^4 10z^3 10z^2 5z^1 1 Is it alternate signs + - + - ...
 
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I think you meant (z-1)^5

but your signs sound correct, consider how many times each must be multiplied by (-1), eg the z term must be multiplied by (-1)^4 so is even
 
Ye sorry I did mean (z-1)^5, if it was (z+1)^5 would that be the same expansion exceot the signs be all positive. Thanks
 

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