Answer: Find Tangent & Normal Line of y=√x/(x+1) at (4, 0.4)

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SUMMARY

The discussion focuses on finding the tangent and normal lines of the curve defined by the function y = √x/(x+1) at the point (4, 0.4). The derivative of the function, calculated as y' = -(x-1)/(2√x(x+1)²), yields a slope of -3/100 at x=4. This slope indicates the steepness of the tangent line at the specified point on the curve. The participant acknowledges a misunderstanding in their initial calculations, highlighting the importance of careful analysis in calculus problems.

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Homework Statement


Find the tangent and normal line through the curve at the given point.
[tex]y = \frac{\sqrt{x}}{x+1}[/tex]
Through point (4, 0.4)

Homework Equations



The Attempt at a Solution



Now, I calculate y' to be:

[tex]y' = \frac{-(x-1)}{2\sqrt{x}(x+1)^2}[/tex]

and so:

y'(4) = (-3/100)

That is the slope at x=4 on the curve y?
 
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I don't see the problem. The slope is -3/100 at the point (4,f(4))=(4,.4).
 
Yeah as soon as I clicked submit I realized what the problem with my thinking was. It's time to take a break for the day..

Thanks for the help!
 

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