Answer Processes in T-V Diagram: A, E, C Explained

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The discussion focuses on the expansion of an ideal monatomic gas in a T-V diagram, identifying processes as isothermal, isobaric, or adiabatic. The participants confirm that process AE is isothermal due to constant temperature, while AC is identified as isobaric because pressure remains constant. There is some confusion regarding the classification of process AE as adiabatic, with clarifications needed on heat flow and changes in internal energy. Additionally, the entropy change during the processes is debated, particularly in relation to adiabatic conditions where no heat is exchanged. The conversation emphasizes the importance of understanding thermodynamic principles to accurately classify these processes.
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An Ideal monatomic gas at initial temperature T_0 (in Kelvins) expands from initial volume V_0 to volume 2V_0 by each of the 5 processes indicated in the T-V diagram. In which process is the expansion a.)isothermal, b.) isobaric or c.)adiabatic? Explain your answers.
d.) In which process does the entropy of the gas decrease.

So far I've said that AE is isothermal, initial and final temperatures are the same.

AC is isobaric, Pressure remains constant

AE is adiabatic, no heat flows in or out of the sytem

Is this right?

I don't know what to do for d.)...
 

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huh? Could you restate the question.
 
wow, sorry. I don't know how that happened? I only hit reply once.

*edit* problem resolved
 
Is adiabatic expansion a heating or cooling process?
 
See edited original post and Attachment.
 
suspenc3 said:
An Ideal monatomic gas at initial temperature T_0 (in Kelvins) expands from initial volume V_0 to volume 2V_0 by each of the 5 processes indicated in the T-V diagram. In which process is the expansion a.)isothermal, b.) isobaric or c.)adiabatic? Explain your answers.
d.) In which process does the entropy of the gas decrease.

So far I've said that AE is isothermal, initial and final temperatures are the same.

AC is isobaric, Pressure remains constant

AE is adiabatic, no heat flows in or out of the sytem

Is this right?
I can't see your diagram yet, but I expect there are 3 choices: a horizontal line (T = constant), a curve where T/V = constant and a curve that goes below that (lower final T) where T/V^{\gamma-1} = constant. I think you can determine from that whether your answers are right.
I don't know what to do for d.)...
For adiabatic dS = dQ/T = 0. But for the others, which way does the heat flow?

AM
 
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Now that I see your graphic of the question, you should check your answer to c).

If volume increases and temperature remains constant, dU does not change but the system does work (dW = PdV). So what can you say about dQ? What is the condition for dQ if it is adiabatic?

AM
 
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