Antenna Resistance: Complex Implications in Real Life

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Seanskahn
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Hello community

Sorry if this is a repost, but I don't find what i am looking for.

I am reading the book "anntenas", by Kraus and Marhefka

In page 30, says the antenna impedances are complex. Z{[tex]\tau[/tex]} = +
R{[tex]\tau[/tex]} + jX{[tex]\tau[/tex]} ..

Could anyone please tell me what does the complex part imply in real life, and why is it regarded as complex.
Thank you

edit: the tau is supposed to be subscripted, but it is appearing as superscript :s
 
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Impedance is used with complex notation for oscillation current. Suppose you have current oscillation at frequency ω and amplitude I0. Then the current is given by:

[tex]I = Re(I_0 e^{i \omega t}) = I_0 cos(\omega t)[/tex]

The complex voltage is related to complex current using analog of Ohm's law.

[tex]V = Re(Z I_0 e^{i \omega t})[/tex]

If Z is real, this is no different from Ohm's Law. But let's substitute your complex form in.

[tex]V = Re((R + iX) I_0 e^{i \omega t})[/tex]

[tex]V = I_0 Re(R e^{i \omega t} + X e^{i (\omega t + \frac{\pi}{2})})[/tex]

[tex]V = I_0 R cos(\omega t) - I_0 X sin(\omega t)[/tex]

The first term is still just IR, but second term is phase-shifted by 90°. This expression can also be re-written using a single cosine function.

[tex]V = I_0 \sqrt{R^2 + X^2} cos(\omega t + \tan^{-1}(\frac{X}{R}))[/tex]

In other words, the norm of Z gives you the ratio of peak voltage to peak current, and so plays a role of effective resistance, while the angle of Z in complex plane gives you the phase shift between voltage and current.
 
hi K2

Thanks you for the reply

then let me ask the next obvious question.
why don't we then just use any 2 dimensional plane for the Z vector?

etheta is still sin(theta) + cos(theta), albeit the sin and cos part is summed, and not distinguishable
 
Because then you can't write V = ZI. Multiplication is not defined in vector spaces, but is defined in complex space.

It's just a convenience, though. You can solve any circuit using ordinary voltage and current by breaking up each into sin and cos components. It just gets a little messy. Once you know a few tricks, working with impedances is very fast.
 
hi K2

thank you very much.