- #1
philrainey
- 90
- 0
A little question when working out the area under a sin wave from 0 degrees to 90 degrees or some lower angle if you take the anti diff of -cosx, does that give the area under the graph assumming the angle is in radians? so enter -cos90=0 subtract -cos0 or-1 the area under the sine wave is 0--1 or one unit (what is this unit) one radian squared?