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Anti diff of sinx

  1. Dec 15, 2008 #1
    A little question when working out the area under a sin wave from 0 degrees to 90 degrees or some lower angle if you take the anti diff of -cosx, does that give the area under the graph assumming the angle is in radians? so enter -cos90=0 subtract -cos0 or-1 the area under the sine wave is 0--1 or one unit (what is this unit) one radian squared?
  2. jcsd
  3. Dec 15, 2008 #2


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    Yes, in a simplified sense, d(sin x)dx = cos x and d(cos x)/dx= -sin x are only true if x is in radians.

    I say "in a simplified sense" because the ways in which sin(t) and cos(t) are defined in more advanced mathematics, t is not an angle at all.
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