Anyone recognize this series expansion?

Click For Summary

Homework Help Overview

The discussion revolves around a series expansion that appears to be related to exponential functions. The original poster presents a series and expresses uncertainty about its pattern and how to manipulate it.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the pattern of the series, questioning the transition between terms and the next term in the sequence. There is an attempt to relate the series to a known function, with some participants suggesting a connection to the exponential function.

Discussion Status

Some participants have provided insights into the nature of the series, suggesting it resembles a known function. There is ongoing exploration of the factorial concept, particularly regarding the definition of 0! and its implications.

Contextual Notes

Participants discuss the definition of factorial, particularly 0!, and its mathematical significance, indicating a broader context of understanding factorials and their properties.

Saladsamurai
Messages
3,009
Reaction score
7
Anyone recognize this series expansion??

[tex]1+3t+\frac{9t^2}{2!}+\frac{27t^3}{3!}+\frac{51t^4}{4!}+...[/tex]

I looks kind of like [itex]e^t[/itex] but i am not sure how to deal with it.

Can I factor something... I kind of suck at these. Someone give me a hint.
 
Physics news on Phys.org
I don't quite see the pattern... how do you get from 27 to 51, and what comes next?
 
nicksauce said:
I don't quite see the pattern... how do you get from 27 to 51, and what comes next?

Oh...yes that should be an 81

[tex] 1+3t+\frac{9t^2}{2!}+\frac{27t^3}{3!}+\frac{81t^4} {4!}+...[/tex]
 
So you have (3t)^0 / 0! + (3t)^1 / 1! + (3t)^2 /2! + (3t)^3 / 3! + ...
Surely you can see what this function is?
 
nicksauce said:
So you have (3t)^0 / 0! + (3t)^1 / 1! + (3t)^2 /2! + (3t)^3 / 3! + ...
Surely you can see what this function is?

I can now! By the way what the Christ is 0! ? I want to say that for some strange reason it is 1... but I don't know why??
 
Saladsamurai said:
I can now! By the way what the Christ is 0! ? I want to say that for some strange reason it is 1... but I don't know why??

0!=1, by definition.
 
cristo said:
0!=1, by definition.

Yeah. That is what I thought... though I thought that there was more to it than 'because the math gods said so.'

But I'll take it if that's all there is to it:smile:
 
Saladsamurai said:
Yeah. That is what I thought... though I thought that there was more to it than 'because the math gods said so.'

But I'll take it if that's all there is to it:smile:

The math gods said so for a good reason. You want the factorial function to satisfy n!=n*(n-1)!. If you put n=1, then you'd better define 0!=1. You can see you're in big trouble trying to define (-1)!. But that's ok. This is also related to the properties of the gamma function. gamma(n+1)=n!. And gamma(1)=1. gamma(0) is undefined, it's a pole of the gamma function. So we'd better leave (-n)! undefined.
 
Saladsamurai said:
Yeah. That is what I thought... though I thought that there was more to it than 'because the math gods said so.'

But I'll take it if that's all there is to it:smile:
0!= 1 because I SAY SO!
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K