AP Physics 1983 Exam: Question #3

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The discussion focuses on AP Physics 1983 Exam Question #3, with participants seeking help in understanding and solving the problem. One user expresses confusion about the question and asks for assistance, indicating that solving it could help with other questions. Another participant suggests that calculating the voltage drop across the parallel resistors is key to solving the problem. The conversation emphasizes the importance of understanding voltage drop calculations in the context of the question. Overall, the thread highlights the collaborative effort to clarify concepts related to the exam question.
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ok it is question #3 from the Ap Physics 1983 exam. http://www.dtfizzix.com/APEXAMS/Phackets/B-1983-Exam.pdf


im not sure how to answer any of the questions and if you could help me I am sure ill be able to solve the other questions like this. thanks
 
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Is there something particular about this question that is confusing? If you know how to calculate the voltage drop over the two parallel resistors, the rest is easy.
 
how do you calculate voltage drop
 
I want to help, but I can't solve the question for you. Have you tried to solve this?
 

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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