Why Does Using A=L^2/4 Lead to Incorrect Results in Calculating EMF in a Loop?

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SUMMARY

The discussion centers on the incorrect application of the area formula A=L^2/4 in calculating electromotive force (EMF) in a wire loop. The user derives the differential area dA as L/2(dl) and subsequently relates it to the velocity v, leading to the erroneous equation -BLv/2R=I. The correct approach requires recognizing that the effective area in the magnetic field is (L/4)*x, which results in the accurate equation -BLv0/4R=I. This highlights the importance of using the appropriate area for flux calculations in electromagnetic contexts.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically Faraday's law of induction.
  • Familiarity with calculus, particularly differentiation and its application in physics.
  • Knowledge of the relationship between area, magnetic flux, and induced EMF.
  • Basic understanding of wire loop geometry in magnetic fields.
NEXT STEPS
  • Study Faraday's law of electromagnetic induction in detail.
  • Learn about calculating magnetic flux through various geometries.
  • Explore the implications of wire loop dimensions on induced EMF.
  • Investigate the effects of changing magnetic fields on induced currents.
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Physics students, electrical engineers, and anyone involved in electromagnetic applications or studying the principles of induction in wire loops.

pokemon123
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Homework Statement
AP Physics C E and M 2
Relevant Equations
emf=d(flux)/dt
I am attempting to solve part b of this question. I start with the equation A=L^2/4 and I get dA=L/2(dl). Next I find dA/dt=L/2(dL/dt) and I realize dL/dt=v. Thus I get -d(flux)/dt=-BLv/2. Finally, I use emf/R=I. I get -BLv0/2R=I. However, the answer is BLv0/4R=I. I understand dA is supposed to equal L/4(dl) but I am confused why starting with the function A=L^2/4 gets me the wrong answer.
 

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pokemon123 said:
I start with the equation A=L^2/4
That's the full area of the wire loop. What you want is the area that is in the magnetic field, which will give you the flux through that loop. Think (L/4)*x.
 

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