AP Physics C E&M RC circuit FRQ

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Homework Help Overview

The discussion revolves around an AP Physics C E&M problem related to an RC circuit, specifically focusing on the behavior of the circuit when a switch is closed. Participants are examining the interactions between a charged capacitor and the circuit components immediately after the switch is activated.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to understand the current flow in the circuit immediately after closing switch S2, questioning how the charged capacitor affects the circuit dynamics. There are discussions about whether the current should change instantaneously or gradually and how to represent this in graphical form.

Discussion Status

Some guidance has been offered regarding the analysis of the circuit at the moment the switch is closed, suggesting that the capacitor can be treated as a voltage source for initial conditions. Multiple interpretations of the capacitor's role and the current behavior are being explored, indicating a productive exchange of ideas without a clear consensus.

Contextual Notes

Participants are working with a specific AP exam question and are referencing scoring guidelines and sample solutions. There is an emphasis on understanding the transition from initial to final states in the circuit, as well as the need to sketch current versus time graphs.

erisedk
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Homework Statement


http://apcentral.collegeboard.com/apc/public/repository/_ap06_frq_physicsc_em_51784.pdf

Please please check out Q2 part (d) on this test

Homework Equations

The Attempt at a Solution


I understand that before S2 is closed, current through the circuit is zero.
As soon as S2 is closed, I don't really understand what happens? I understand that both the currents will be ε/R1+R2 after some time, but I don't get how the capacitor which is completely charged, interacts with the circuit right after S2 is closed.

Additionally, please explain how the graphs will be drawn.
 
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erisedk said:
but I don't get how the capacitor which is completely charged, interacts with the circuit right after S2 is closed.
The current doesn't flow through the capacitor, hence take into consideration of only the resistors,
 
erisedk said:
I understand that before S2 is closed, current through the circuit is zero.
As soon as S2 is closed, I don't really understand what happens? I understand that both the currents will be ε/R1+R2 after some time, but I don't get how the capacitor which is completely charged, interacts with the circuit right after S2 is closed.
For purposes of analyzing a circuit for the instant after a switch has changed it, you may replace a capacitor with a voltage source having a voltage equal to that of the capacitor immediately before the switching. Perhaps that will help you to sort out the conditions.
Additionally, please explain how the graphs will be drawn.
Find initial currents at t = 0. Find final currents at t → ∞ (steady state). Connect initial and final states with suitable exponential curves.
 
Last edited:
Check the following thread. It may help.
Jzhang27143 said:

Homework Statement


The circuit in the link below contains a capacitor of capacitance C, a power supply of emf E, two resistors of resistances R1 and R2, and two switches S1 and S2. After switch S1 has been closed for a long time, switch S2 gets closed at a time t = 0. Sketch graphs of the current I1 in R1 and I2 in R2 versus time.
https://www.physicsforums.com/threads/rl-parallel-circuit-ap-2006.812704/
 

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