Aperture stop for an optical system

  • Thread starter Thread starter fog37
  • Start date Start date
  • Tags Tags
    Optical System
AI Thread Summary
The aperture stop (AS) of an optical system limits light from the object and is determined by the on-axis object point. It is questioned whether the AS for this point also applies to off-axis points. The discussion suggests that moving a 2D object along the optical axis changes the AS, implying it is not a fixed value. However, a counterpoint asserts that the aperture setting, such as f2.8, remains constant regardless of the object's position. This highlights a debate on whether the AS is influenced by the object's location in 3D space.
fog37
Messages
1,566
Reaction score
108
Hello Forum,

The aperture stop (AS) of an optical system is that physical aperture in the system that limits the amount of light from the object.
Consider a 2D object formed by point objects. The AS is determined by considering the object point that is located on the optical axis. Will the AS for that on-axis point also represent the AS for all the other off-axis objet points forming the object?

If the same 2D object moves to a different position along the optical axis, the AS will change since it is determined by the on-axis object point and its location, correct?

If that is correct, it seems that the AS is not fixed aperture for the optical system but strongly depends on the position of the 3D object being imaged...

Thanks,
fog37
 
Science news on Phys.org
fog37 said:
If the same 2D object moves to a different position along the optical axis, the AS will change since it is determined by the on-axis object point and its location, correct?

not sure how you come to that conclusion. If I set a f2.8 aperture on my camera lens. it stays at f2.8 regardless of how far or close an object is to the lens or whether it in the axis line of the lens or off to one side of that axis

fog37 said:
If that is correct, it seems that the AS is not fixed aperture for the optical system but strongly depends on the position of the 3D object being imaged...

refer to my previous comment

cheers
Dave
 
Back
Top