Applications of Partial Derivatives and chain rule

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SUMMARY

The discussion focuses on the application of partial derivatives and the chain rule to determine the rate of change of a box's volume given changing dimensions. The specific scenario involves a rectangular box with dimensions a=1m, b=2m, and c=3m, with rates of change da/dt = db/dt = 1m/sec and dc/dt = -3m/sec. The calculated rate of change of volume is confirmed to be 3m³/s using the formula ∂V/∂t=(bc)(da/dt)+(ac)(db/dt)+(ab)(dc/dt). The solution is validated by participants in the discussion.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with the chain rule in calculus
  • Basic knowledge of volume calculations for rectangular prisms
  • Ability to perform substitution in mathematical equations
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Explore advanced topics in partial derivatives
  • Learn about real-world applications of volume change in physics
  • Practice problems involving rates of change in geometric contexts
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Students studying calculus, particularly those focusing on multivariable functions, as well as educators and tutors looking for practical examples of applying partial derivatives and the chain rule.

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Homework Statement



The lengths a,b,c of a rectangle are changing with time. At the instant in question, a=1m, b=2m, c=3m and da/dt = db/dt = 1m/sec, and dc/dt = -3m/sec. At what rate is the box's volume changing at this instant?

Homework Equations



Chain rule for partial derivatives.

The Attempt at a Solution



∂V/∂t=(bc)(da/dt)+(ac)(db/dt)+(ab)(dc/dt)

Substituting the values gives 3m^3/s. Am I right?
Thanks for helping me out. The answer is not given in the book.
 
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The equation is correct.
 
Thanks!

Hey! Thanks a ton for the re-assurances! Makes me feel more confident about myself.
 

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