Applied Force to a Sliding Frictionless Ramp

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SUMMARY

The problem involves calculating the horizontal force F required to keep a block of mass m stationary on a frictionless ramp of mass M inclined at an angle θ. The correct formula for this force is F = (m + M) * g * tan(θ). The discussion emphasizes the importance of analyzing the forces acting on both the block and the ramp system, applying Newton's laws effectively, and ensuring that the normal force is accurately determined by considering the vertical forces acting on the block.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Knowledge of force diagrams and free-body diagrams
  • Familiarity with trigonometric functions, specifically tangent
  • Concept of normal force in inclined planes
NEXT STEPS
  • Study the derivation of forces on inclined planes in classical mechanics
  • Learn about free-body diagrams and their applications in solving physics problems
  • Explore the implications of frictionless surfaces in dynamics
  • Investigate the relationship between mass, acceleration, and force in multi-body systems
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of force analysis in inclined planes.

Rook2012
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Homework Statement



Hello all, kinda angry at myself for posting this but my brain has hit a brick wall.
This is an easy problem too... anyway.

A frictioness ramp of mass M and incline θ sits on a frictionless surface. A block of mass m sits on the ramp. What horizontal force F must be applied to the ramp to ensure the block does not move?

Homework Equations



F = ma
Newton's Third Law

The Attempt at a Solution



I know the answer is (m+M)*g*tan(θ). But I'm having trouble making myself believe it.

I started with a force diagram of the block, the only 2 forces acting on it are gravity directly downward and the normal force (N) at an angle of θ above the horizontal.

So the net force on the block is F_{block} = N sin(θ) i + (mg-(N cos(θ)) j = ma

Then I looked at the ramp+block system and determined
F_{system} = (M+m)a_{system}

Here for some reason the gears stop turning. I went on to say that the y components on the block sum to zero, so the Normal force is \frac{mg}{cosθ}.

From here I substitued in for N in the x direction and then equated "a" in both equations but I know that's wrong. Got me the right answer, but its the wrong way of doing it. Any help would be appreciated.
 
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Come to think of it, equating the acceleration of the system and the block is alright isn't it? They are both moving at the same acceleration which is all in the x direction.

If I let ma = Nsin(theta) because the forces in the vertical direction cancel, and then solve for "a" as I did... maybe that it the right way to go about it. Let me know if I'm delusional, peace.
 
Rook2012 said:
Come to think of it, equating the acceleration of the system and the block is alright isn't it? They are both moving at the same acceleration which is all in the x direction.
yes, correct
If I let ma = Nsin(theta) because the forces in the vertical direction cancel, and then solve for "a" as I did... maybe that it the right way to go about it. Let me know if I'm delusional, peace.
yes, just be sure to determine N by looking at sum of forces in the vertical y direction = 0.
 

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