Apply conservation of momentum to the collision

AI Thread Summary
The discussion revolves around a physics problem involving two equal-mass automobiles colliding at an intersection, with one traveling east and the other north. The key focus is on applying the conservation of momentum to determine the initial speed of the northbound vehicle, given that they become stuck together after the collision. Participants suggest setting up momentum equations for both the x and y components to find the unknown speed of the northbound vehicle. The final speed after the collision is also a point of confusion, but it's clarified that the actual mass values are not necessary for the calculations. The discussion concludes with a participant confirming their understanding of the approach.
~christina~
Gold Member
Messages
714
Reaction score
0

Homework Statement



2 automobiles of equal mass approach an intersection. One vehicle is traveling with a velocity of 13.0m/s toward east and other is traveling north with a speed of v_2i. The vehicles collide at the intersection become stuck together and leave parallel skid lines at an angle of 55.0 deg north of east. Speed limit for both cars is 35mi/h and the driver of th northward moving vehicle claims he was within speed limit when it occured. Is he telling truth?

Homework Equations





The Attempt at a Solution



I don't have the masses so how do I do this problem??

I don't have the v2 so I assume I could work with 35mph speed as the initial speed of the other vehicle but other than that I'm not sure what to do... and I don't have final vf after collison

35mph=> 15.646m/s


Help!
 
Last edited:
Physics news on Phys.org
Call the mass of each car "m". You won't need the actual value.

Apply conservation of momentum to the collision. Set up two equations, one for the x-components (East) and one for the y-components (North). Call the final speed vf.

You should be able to solve for v2.
 
Thank You Doc Al

I got it.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top