What is the Maximum Product of Two Numbers that Sum to 120?

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To find the maximum product of two numbers that sum to 120, define the variables x and y such that x + y = 120. The product can be expressed as P = xy, which can be simplified to P = y(120 - y) by substituting x with 120 - y. To maximize this function, one can either use calculus to find the derivative or recognize that the product forms a parabola, with the maximum occurring at the vertex. The vertex can be determined without calculus, leading to the maximum product. The discussion emphasizes both algebraic manipulation and graphical interpretation for solving the problem.
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1. Find two numbers x and y whose sum is 120 and whose product is a maximum.



2. none



3. x + y = 120
xy = maximum
x = 120 - y
I wrote these down but I don't know what to do next. Can you please show me? :) Thank You!
 
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Well you have the function P = xy which you want to maximize, however it contains two variables. Are they independent though? How can you reduce this function down to a single variable function?
 
whitehorsey said:
1. Find two numbers x and y whose sum is 120 and whose product is a maximum.



2. none



3. x + y = 120
xy = maximum
x = 120 - y
I wrote these down but I don't know what to do next. Can you please show me? :) Thank You!
Replace the x in xy with 120- y so you have only one variable. Now, do you know how to "apply the derivative" to find where a function has a maximum or minimum?
 
As an alternate approach, the graph of your area function, as a function of either x or y alone, is a parabola. You can find the vertex of the parabola, at which the maximum area is attained, without using calculus.
 
Ah! Excellent point.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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