Arc Length Need Verification, If Wrong, Can You Help?

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SUMMARY

The discussion focuses on verifying the arc length of the curve defined by the equation y = 1/2(e^x - e^(-x)) from 0 to 2. The arc length formula used is s = ∫√[1+(dy/dx)^2] dx, leading to an expression involving hyperbolic functions. The correct interpretation of the curve as y(x) = sinh(x) simplifies the integration process significantly. The calculated arc length is approximately 3.323971.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques.
  • Familiarity with hyperbolic functions and their properties.
  • Knowledge of differential calculus to compute dy/dx.
  • Experience with definite integrals and arc length calculations.
NEXT STEPS
  • Study hyperbolic functions and their derivatives, focusing on sinh(x) and cosh(x).
  • Learn advanced integration techniques, particularly for integrals involving square roots.
  • Explore the application of arc length formulas in different coordinate systems.
  • Practice solving arc length problems for various types of curves.
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Students studying calculus, mathematics educators, and anyone interested in mastering arc length calculations and hyperbolic functions.

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Homework Statement



Length of curve: y=1/2(ex-e-x) from 0 to 2


Homework Equations



s = ∫√[1+(dy/dx)^2] dx

The Attempt at a Solution



[sqrt(4+2e^(-x)+e^x)]*[-1+e^x]/[1+e^x].
= 3.323971
 
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Your notation is ambiguous. I'm guessing that your curve is,

[tex]y(x) = \frac{e^x-e^{-x}}{2}[/tex]

In which case it may be useful to note that,

[tex]\frac{e^x-e^{-x}}{2} = \sinh(x)[/tex]

Which (along with a hyperbolic identity) would greatly simplify your integrand.
 

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