Are Fock States Eigenstates for the Operators a^{\dagger} and a?

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Homework Help Overview

The discussion revolves around the properties of Fock states in the context of quantum mechanics, specifically whether they are eigenstates of the creation and annihilation operators.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of eigenstates and apply the operators to Fock states, questioning the results and their implications.

Discussion Status

Some participants have provided insights into the nature of eigenstates and clarified that Fock states do not satisfy the eigenstate condition for the given operators. There is an ongoing exploration of the implications of these findings.

Contextual Notes

Participants are navigating the definitions and properties of quantum states, with some confusion regarding the terminology and the specific characteristics of Fock states versus coherent states.

Ylle
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Homework Statement



I have to show that the Fock states are eigenstates for the operators {{\hat{a}}^{\dagger }} and/or {\hat{a}}

And I'm not totally sure how to show this.


Homework Equations



?


The Attempt at a Solution



I know that if I use the operators on a random Fock state i get:

a^{\dagger}|n\rangle=\sqrt{n+1}|n+1\rangle
a|n\rangle=\sqrt{n}|n-1\rangle

So what's next ?


Regards
 
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Are you sure you are typing the question correctly? Because as you just showed, Fock states are not eigenstates of the creation and annihilation operators. Maybe you are getting it confused with coherent states.
 
Ahhh...
It said: IS the Fock states eigenstates for the operators, doh...

So when I use the operators on the Fock state, they are not eigenstates because of the |n-1> and |n+1> at the end, which should have been just |n> in each case, or am I way off ?
 
Yes, an eigenstate of an operator won't change under an operation on the operator. So you would just get back |n> with a coefficient called the eigenvalue.
 
Well, thank you :)
Didn't know it was that easy.
 

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